feat(attr): AttributeFormula 公式模块——hybrid 连乘 / inverse 反向下限 / add_int 拒 pct
公式集中于单一纯静态模块,无状态零依赖,故可脱离游戏进程单元断言。 乘算用连乘而非线性求和:三条 +20% 得 ×1.728 而非 ×1.6,避免后期线性失控。 add_int 对离散预算拒绝 pct 并 push_error,而非静默取整掩盖配置错误。 Co-Authored-By: Claude Opus 5 <noreply@anthropic.com>
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## AttributeFormula — 属性合成公式的唯一实现处
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## 纯静态函数:无状态、不依赖 PlayerStats / EventBus / 场景树,故可脱离游戏进程单元测试
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## 权威来源:docs_dev/specs/2026-07-31-player-attributes-design.md §2.1 / §2.3
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class_name AttributeFormula
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extends RefCounted
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enum Combine { HYBRID, INVERSE, ADD_INT }
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const _COMBINE_NAMES: Dictionary = {
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"hybrid": Combine.HYBRID,
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"inverse": Combine.INVERSE,
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"add_int": Combine.ADD_INT,
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}
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## JSON 的 combine 字符串 → 枚举;未知值 push_error 并回退 HYBRID
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static func combine_from_string(s: String) -> Combine:
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if _COMBINE_NAMES.has(s):
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return _COMBINE_NAMES[s]
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push_error("AttributeFormula: 未知 combine「%s」,回退 hybrid" % s)
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return Combine.HYBRID
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## 唯一的公式入口
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## base —— attributes.json 的基准值
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## mods —— [{"mode": "flat"|"pct", "value": float}, ...];调用方负责只传本属性的加成
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## attr_def —— attributes.json 中该属性的定义(读 combine / hard)
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## 返回统一为 float;add_int 属性由调用方做 int() 转换(公式模块不感知目标字段类型)
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static func compute(base: float, mods: Array, attr_def: Dictionary) -> float:
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var combine: Combine = combine_from_string(String(attr_def.get("combine", "hybrid")))
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var hard: float = float(attr_def.get("hard", 0.0))
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var flat_sum: float = 0.0
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var pct_prod: float = 1.0
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for m in mods:
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var mode: String = String(m.get("mode", "flat"))
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var v: float = float(m.get("value", 0.0))
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if mode == "flat":
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flat_sum += v
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elif mode == "pct":
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if combine == Combine.ADD_INT:
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push_error("AttributeFormula: add_int 属性不接受 pct 加成(value=%f),已忽略" % v)
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continue
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# 连乘而非线性求和:三条 +20% = ×1.728 而非 ×1.6,避免后期线性失控
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pct_prod *= (1.0 + v) if combine == Combine.HYBRID else (1.0 - v)
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else:
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push_error("AttributeFormula: 未知 mode「%s」,已忽略" % mode)
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match combine:
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Combine.ADD_INT:
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var ri: float = floorf(base + flat_sum)
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return clampf(ri, 0.0, hard) if hard > 0.0 else maxf(0.0, ri)
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Combine.INVERSE:
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# 越低越快:hard 是**下限**
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return maxf(hard, (base + flat_sum) * pct_prod)
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_:
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var r: float = maxf(0.0, (base + flat_sum) * pct_prod)
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return minf(r, hard) if hard > 0.0 else r # hard=0.0 约定为「不钳制」
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