对 E1~E3 修复后的实现做取证式复核:把 design 的判定语句做成可执行探针直接 打在代码上(§5.1/§5.2 跟牌层级、§8.1 算奖连对链、§7 算子逐档、§5.4 甩牌最大性、 §6.3 扣底、§8.4 三条支付线、§4/§9/§10/§11 流程与门控),未发现新的不一致。 新增 test/test_endgame.js:用真实发牌跑完整一局(叫分→上庄→选主→埋牌→28 轮 出牌→小局结算)并校验与牌面无关的不变量(牌张守恒 84/8/16、捡分=闲家赢得分牌 +扣底分、X 分配庄±2X/闲∓X、算奖 X×(2Ni−Nj−Nk)、零和、result 与判定一致), 另覆盖投降局与中途解散两条支线。连跑 10 次无抖动,全套单测 389 项通过。 合规文档补记「第四轮·复验」取证表。 Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
96 lines
5.6 KiB
JavaScript
96 lines
5.6 KiB
JavaScript
// L4 端到端:用真实发牌跑完整一局(叫分→上庄→选主→埋牌→28轮出牌→小局结算),
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// 校验 design §12.1 的流程闭合与一批与牌面无关的不变量(牌张守恒/捡分一致/结算零和/分配公式)。
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// 另覆盖 §4.4 投降局与 §12.2 中途解散两条支线。
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// 说明:牌是随机发的,但断言的都是**与具体牌面无关**的不变量,不会因发牌不同而抖动。
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const { mod, setup } = require('./_rpc.js');
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const t = require('./_assert')();
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const P = global.cls_youle_erqiwang_paiju;
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const AR = global.cls_youle_erqiwang_arith;
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const pk = (seat, d) => ({ conmode: 0, fromid: seat, data: Object.assign({ agentid: 1, playerid: seat, gameid: 1, roomcode: 1, seat: seat }, d || {}) });
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// 开局并让 0 号位以 call 分坐庄(另两家不叫)
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function seatBanker(roomtype, call) {
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const pj = P.new({ paiju_list: [] }, 0);
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const ctx = setup(roomtype, pj);
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mod.jiaofen(pk(pj.method.get_callgrade_seat(), { call: call }));
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mod.jiaofen(pk(pj.method.get_callgrade_seat(), { call: 0 }));
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mod.jiaofen(pk(pj.method.get_callgrade_seat(), { call: 0 }));
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return { pj, ctx };
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}
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// 出牌驱动:首家出手上最小的单张,跟家取第一张能通过 can_followcard 的牌
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function playAll(pj) {
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let guard = 0;
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while (pj.step === 5 && ++guard < 200) {
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const seat = pj.playproc.currseat, hand = P.get_seat_cards(pj, seat);
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let pick = null;
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if (seat === pj.playproc.start) {
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pick = [hand[hand.length - 1]];
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} else {
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for (const c of hand) {
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if (AR.can_followcard(pj.flower, hand, [c], pj.playproc.startcount, pj.playproc.startflower, pj.playproc.starttype).result) { pick = [c]; break; }
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}
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}
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if (!pick) { return false; }
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mod.chupai(pk(seat, { cards: pick }));
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}
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return pj.step === 6;
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}
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// ============ §12.1 正常局全流程 ============
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const { pj, ctx } = seatBanker("00000", 65);
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t.eq('§4.2 坐庄(banker/call/step)', [pj.banker, pj.call, pj.step], [0, 65, 2]);
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t.eq('§4.3 庄家摸暗牌后36张 / 闲家28张', [P.get_seat_cards(pj, 0).length, P.get_seat_cards(pj, 1).length], [36, 28]);
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mod.xuanzhu(pk(0, { flower: 1 }));
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t.eq('§4.4 选主后进埋牌阶段', [pj.flower, pj.step], [1, 3]);
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mod.maipai(pk(0, { cards: P.get_seat_cards(pj, 0).slice(-8) }));
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t.eq('§4.5 埋牌后庄家28张、进出牌阶段', [P.get_seat_cards(pj, 0).length, pj.step], [28, 5]);
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t.eq('§5.1 第一轮固定由庄家先出', [pj.playproc.round, pj.playproc.start], [1, 0]);
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t.eq('§5/§6 28轮打完进入结算', playAll(pj) && pj.playproc.round, 28);
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t.eq('§2 牌张守恒(出84 / 埋8 / 去掉3-4共16)',
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[pj.cards.filter(c => c.playround > 0).length, pj.cards.filter(c => c.playround === 0).length, pj.cards.filter(c => c.number === 3 || c.number === 4).length],
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[84, 8, 16]);
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const last = ctx.sent[ctx.sent.length - 1];
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const aset = last.data.aset;
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t.eq('结算包 rpc/success', [last.rpc, last.data.success], ['jiesuan', true]);
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t.eq('§11 结束亮出底牌8张', last.data.bottom.cards.length, 8);
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// §6.2/§6.3:闲家捡分 = 闲家赢下的分牌 + 扣底(可能翻倍)分
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let jian = 0;
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for (const c of pj.cards) { if (c.playowner > -1 && c.playowner !== pj.banker) { jian += c.score; } }
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const bonus = last.data.bottom.grade2 || 0;
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t.eq('§6.2/§6.3 捡分 = 闲家赢得分牌 + 扣底分', aset.grade, jian + bonus);
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// §6.3:扣底只在「闲家用主牌赢下末轮」时发生
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const lastWinIsXian = pj.playproc.maxseat !== pj.banker;
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const lastMult = lastWinIsXian ? AR.get_bottom_multiple(pj.flower, pj.playproc.cards[pj.playproc.maxseat]) : 0;
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t.eq('§6.3 扣底触发条件(闲家 + 主牌)', lastMult > 0, !!last.data.bottom.multiple);
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// §7 第3层:X = 基础子数 × |判定倍率|,庄家 ±2X、闲家各 ∓X
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const X = aset.multiple * Math.abs(aset.upgrade);
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const win = aset.upgrade > 0 ? 1 : -1;
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t.eq('§7 捡分子数分配 庄±2X / 闲各∓X', aset.seatlist.map(p => p.grade_jf), [win * X * 2, -win * X, -win * X]);
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// §8.4 第4层:算奖线 X×(2Ni−Nj−Nk)
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const N = aset.seatlist.map(p => p.naward);
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t.eq('§8.4 算奖分配 X×(2Ni−Nj−Nk)', aset.seatlist.map(p => p.grade_aw),
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[X * (2 * N[0] - N[1] - N[2]), X * (2 * N[1] - N[0] - N[2]), X * (2 * N[2] - N[0] - N[1])]);
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t.eq('本局结算零和', aset.seatlist.reduce((s, p) => s + p.grade, 0), 0);
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t.eq('§4.6 result 与判定一致(0庄赢/1闲赢)', pj.result, aset.upgrade > 0 ? 0 : 1);
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// ============ §4.4 / §7.1 投降局 ============
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const tx = seatBanker("00000", 70);
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t.eq('§4.3 70分坐庄:暗牌亮3秒标志 + 闲家也收到暗牌',
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[tx.ctx.sent[tx.ctx.sent.length - 1].data.ancard3s, tx.ctx.sent[tx.ctx.sent.length - 2].data.bottomcards.length], [1, 8]);
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mod.touxiang(pk(0));
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const txa = tx.ctx.sent[tx.ctx.sent.length - 1].data.aset;
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t.eq('§7.1 投降:base=1 / 庄-2、闲各+1', [txa.multiple, txa.seatlist.map(p => p.grade_jf)], [1, [-2, 1, 1]]);
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t.eq('§4.4 投降不选主、不埋牌', [tx.pj.flower, tx.pj.cards.filter(c => c.playround === 0).length], [-1, 0]);
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t.eq('§8.4 投降算奖按庄家36张快照', P.get_seat_cards_award(tx.pj, 0).length, 36);
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t.eq('§4.6 投降 result=2(下家坐庄)', tx.pj.result, 2);
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// ============ §12.2 中途解散 ============
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const ds = seatBanker("00000", 65);
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mod.xuanzhu(pk(0, { flower: 1 }));
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const dsmsg = require('../class.export.js').new().get_disbandRoom(ds.ctx.o_room);
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t.eq('§12.2 解散:不结算子数、result=3', [dsmsg.data.aset.multiple, dsmsg.data.aset.seatlist.map(p => p.grade), ds.pj.result], [0, [0, 0, 0], 3]);
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process.exit(t.done('endgame') ? 0 : 1);
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