joywayerandClaude Opus 5
47c8a27d0d
三条 chupai3 用例（不带 grade 那条、跨包累加的两条）之前都带了 nextseat 字段却没验证它，读起来像遗漏，也让"chupai3 同样会推进控制权"这件事只被 验证了一次。补齐后四条 chupai3 用例均验证 turn.seat；跨包累加的两条从 turn.seat 由 0 变 1，顺带证明了第二个包确实被处理，不只是看 grade 一个数字。 只改测试文件，PlayHandler.js 未改动。 Co-Authored-By: Claude Opus 5 (1M context) <noreply@anthropic.com>
92 lines
4.5 KiB
JavaScript
92 lines
4.5 KiB
JavaScript
// 出牌 handler（chupai1/2/3）
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const { load } = require('./_load');
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const t = require('./_assert')();
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load('client/js/gameabc-framework/system/EventBus.js');
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load('client/js/01_SubGame/codes/state/Events.js');
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load('client/js/01_SubGame/codes/state/GameState.js');
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load('client/js/01_SubGame/codes/net/handlers/PlayHandler.js');
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const S = EQW_GameState;
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const evts = [];
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Object.keys(EQW_Events).forEach(k => EventBus.on(EQW_Events[k], () => evts.push(k)));
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// ================= chupai1（首家出牌，自己出的）=================
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S.reset(); S.room.mySeat = 0; S.my.cards = [1,2,3,4]; evts.length = 0;
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EQW_PlayHandler.handle({ success: true, seat: 0, cards: [1,2], count: 2, flower: 3,
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cardtype: 201, nextseat: 1, countdown: 15, baozhu: 0,
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cardsinhand: [3,4], curmultiple: 2,
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seatlist: [[0,0,0,0,[5,2]],[0,0,0,0,[6,1]],[0,0,0,0,[7,3]]] }, 1);
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t.eq('出牌者手牌被更新', S.my.cards, [3,4]);
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t.eq('下一个出牌者', S.turn.seat, 1);
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t.eq('倒计时', S.turn.countdown, 15);
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t.eq('抓分倍数', S.aset.curmultiple, 2);
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t.eq('牌况表', S.table.seatlist.length, 3);
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t.eq('出牌发事件', evts.indexOf('EQW_CARD_PLAYED') >= 0, true);
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// ================= chupai2（别人出牌）=================
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// 别人出牌时没有 cardsinhand，不能抹掉自己的手牌
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S.reset(); S.room.mySeat = 0; S.my.cards = [3,4]; evts.length = 0;
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EQW_PlayHandler.handle({ success: true, seat: 1, cards: [5,6], nextseat: 2,
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countdown: 15, baozhu: 0 }, 2);
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t.eq('别人出牌不抹自己手牌', S.my.cards, [3,4]);
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t.eq('控制权推进', S.turn.seat, 2);
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// mustcard 只发给下一个出牌者
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S.reset(); S.room.mySeat = 2;
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EQW_PlayHandler.handle({ success: true, seat: 1, cards: [5,6], nextseat: 2,
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countdown: 15, mustcard: [7,8] }, 2);
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t.eq('必出牌', S.my.mustCard, [7,8]);
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// 没有 mustcard 时要清空——否则上一轮的建议会残留
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S.reset(); S.my.mustCard = [7,8];
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EQW_PlayHandler.handle({ success: true, seat: 1, cards: [5,6], nextseat: 0, countdown: 15 }, 2);
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t.eq('无 mustcard 时清空', S.my.mustCard, []);
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// ================= chupai3（末家出牌，本轮结束）=================
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// 真实的 chupai3 也带 nextseat（下一轮首家）：服务端在 switch 前统一设置，
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// 只有整轮结束进入结算时才会整体换成 jiesuan rpc（不会以 chupai3 到达 handler）
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S.reset(); evts.length = 0;
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EQW_PlayHandler.handle({ success: true, seat: 2, cards: [9,10], maxseat: 0, grade: 25,
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nextseat: 0, countdown: 15, baozhu: 1, curmultiple: -2 }, 3);
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t.eq('本轮最大者', S.result.chupai.maxseat, 0);
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t.eq('本轮闲家得分', S.result.chupai.grade, 25);
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t.eq('累计捡分', S.aset.grade, 25);
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t.eq('报无主标志', S.aset.baozhu, 1);
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t.eq('抓分倍数（带符号）', S.aset.curmultiple, -2);
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t.eq('下一轮首家', S.turn.seat, 0);
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t.eq('本轮结束发事件', evts.indexOf('EQW_TRICK_END') >= 0, true);
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// 本轮闲家没得分时不带 grade，累计分不该被抹
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S.reset(); S.aset.grade = 40;
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EQW_PlayHandler.handle({ success: true, seat: 2, cards: [9,10], maxseat: 1,
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nextseat: 1, countdown: 15 }, 3);
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t.eq('无 grade 时累计分保持', S.aset.grade, 40);
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t.eq('无 grade 时仍推进控制权', S.turn.seat, 1);
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// grade 是「本轮」得分，要跨包累加进小局捡分，不是赋值——
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// 若实现改成 aset.grade = data.grade，这条会把 25 覆盖成 15 而非累加到 25
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S.reset();
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EQW_PlayHandler.handle({ success: true, seat: 2, cards: [1,2], maxseat: 0, grade: 10,
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nextseat: 0, countdown: 15 }, 3);
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t.eq('第一轮捡分', S.aset.grade, 10);
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t.eq('第一轮下一轮首家', S.turn.seat, 0);
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EQW_PlayHandler.handle({ success: true, seat: 2, cards: [3,4], maxseat: 1, grade: 15,
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nextseat: 1, countdown: 15 }, 3);
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t.eq('第二轮跨包累加捡分', S.aset.grade, 25);
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t.eq('第二轮下一轮首家（证明第二个包确被处理）', S.turn.seat, 1);
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// ================= 甩错 =================
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S.reset(); evts.length = 0;
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EQW_PlayHandler.handle({ success: true, seat: 0, cards: [11], shuaicuo: 1, count: 1,
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flower: 3, cardtype: 101, nextseat: 1, countdown: 15 }, 1);
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t.eq('甩错标志', S.table.playproc.shuaicuo, 1);
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// ================= 缺必需字段 =================
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S.reset();
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EQW_PlayHandler.handle({ success: true, cards: [1] }, 1); //缺 seat
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t.eq('缺 seat 时跳过该包', S.turn.seat, -1);
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process.exit(t.done('handlers_play') ? 0 : 1);
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